What are the solutions to the equation -4x^2-24x+64=0 ?

The solutions to the equation -4x^2-24x+64=0 are x=-8,x=2

Find the zeros of -4x^2-24x+64=0

The zeros of -4x^2-24x+64=0 are x=-8,x=2

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- 4 x^{2} - 24 x + 64 = 0

x = - 8, x = 2

Solution steps

- 4 x^{2} - 24 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 4 ) \cdot 64}{2 ( - 4 )}

(- 24)^{2} - 4 (- 4) \cdot 64 = 40

x_{1, 2} = \frac{- ( - 24 ) \pm 40}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 40}{2 ( - 4 )}, x_{2} = \frac{- ( - 24 ) - 40}{2 ( - 4 )}

x = \frac{- ( - 24 ) + 40}{2 ( - 4 )} : - 8

x = \frac{- ( - 24 ) - 40}{2 ( - 4 )} : 2

The solutions to the quadratic equation are:

x = - 8, x = 2

x^{2} - 11 x + 10 = 0

s^{2} - s + 4

x^{2} - 6 x + 9

25 x^{2} + 40 x - 9 = 0

10 - 2 x^{2} = - 198

What are the solutions to the equation -4x^2-24x+64=0 ?
The solutions to the equation -4x^2-24x+64=0 are x=-8,x=2
Find the zeros of -4x^2-24x+64=0
The zeros of -4x^2-24x+64=0 are x=-8,x=2