What are the solutions to the equation completesquare 25x^2+40x-9=0 ?

The solutions to the equation completesquare 25x^2+40x-9=0 are x= 1/5 ,x=-9/5

Find the zeros of completesquare 25x^2+40x-9=0

The zeros of completesquare 25x^2+40x-9=0 are x= 1/5 ,x=-9/5

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25 x^{2} + 40 x - 9 = 0

x = \frac{1}{5}, x = - \frac{9}{5}

Decimal Notation

x = 0.2, x = - 1.8

Solution steps

25 x^{2} + 40 x - 9 = 0

Move

9

to the right side

25 x^{2} + 40 x = 9

Divide both sides by

25

\frac{25 x ^{2} + 40 x}{25} = \frac{9}{25}

x^{2} + \frac{8 x}{5} = \frac{9}{25}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{4}{5})^{2} = 1

For

the solutions are

f (x) = a, - a

Solve

x + \frac{4}{5} = 1 : x = \frac{1}{5}

Solve

x + \frac{4}{5} = - 1 : x = - \frac{9}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{9}{5}

10 - 2 x^{2} = - 198

y, y = x y + x^{2} + 1

y, x^{2} + x y + y^{2} = 9

- 7 x = 3 - 4 x^{2}

6 + 3 x^{2} = 18

What are the solutions to the equation completesquare 25x^2+40x-9=0 ?
The solutions to the equation completesquare 25x^2+40x-9=0 are x= 1/5 ,x=-9/5
Find the zeros of completesquare 25x^2+40x-9=0
The zeros of completesquare 25x^2+40x-9=0 are x= 1/5 ,x=-9/5