What is the answer to solvefor y,y=xy+x^2+1 ?

The answer to solvefor y,y=xy+x^2+1 is y=(x^2+1)/(1-x);\quad x\ne 1

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solvefor y,y=xy+x^2+1

solve for

y, y = x y + x^{2} + 1

y = \frac{x ^{2} + 1}{1 - x}; x \neq = 1

Solution steps

y = x y + x^{2} + 1

Move

x y

to the left side

y - x y = x^{2} + 1

Factor

y - x y : y (1 - x)

y (1 - x) = x^{2} + 1

Divide both sides by

1 - x; x \neq = 1

y = \frac{x ^{2} + 1}{1 - x}; x \neq = 1

y, x^{2} + x y + y^{2} = 9

- 7 x = 3 - 4 x^{2}

6 + 3 x^{2} = 18

s^{2} + 2 s + 4

100 = x^{2} - 28 x + 296

What is the answer to solvefor y,y=xy+x^2+1 ?
The answer to solvefor y,y=xy+x^2+1 is y=(x^2+1)/(1-x);\quad x\ne 1