What are the solutions to the equation 100=x^2-28x+296 ?

The solutions to the equation 100=x^2-28x+296 are x=14

Find the zeros of 100=x^2-28x+296

The zeros of 100=x^2-28x+296 are x=14

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100 = x^{2} - 28 x + 296

x = 14

Solution steps

100 = x^{2} - 28 x + 296

Switch sides

x^{2} - 28 x + 296 = 100

Move

100

to the left side

x^{2} - 28 x + 196 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 1 \cdot 196}{2 \cdot 1}

(- 28)^{2} - 4 \cdot 1 \cdot 196 = 0

x_{1, 2} = \frac{- ( - 28 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 28 )}{2 \cdot 1}

\frac{- ( - 28 )}{2 \cdot 1} = 14

x = 14

The solution to the quadratic equation is:

x = 14

(- 2 x + 1) (- 2 x - 7) = 0

w^{2} + 7 w + 4 = 0

z^{2} + 0.35 z - 1.125 = 0

x^{2} - 7 x - 1 = - 1

x^{2} + 6 x + 8

What are the solutions to the equation 100=x^2-28x+296 ?
The solutions to the equation 100=x^2-28x+296 are x=14
Find the zeros of 100=x^2-28x+296
The zeros of 100=x^2-28x+296 are x=14