What are the solutions to the equation 10b^2+21b+6=2b ?

The solutions to the equation 10b^2+21b+6=2b are b=-2/5 ,b=-3/2

Find the zeros of 10b^2+21b+6=2b

The zeros of 10b^2+21b+6=2b are b=-2/5 ,b=-3/2

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10 b^{2} + 21 b + 6 = 2 b

b = - \frac{2}{5}, b = - \frac{3}{2}

Decimal Notation

b = - 0.4, b = - 1.5

Solution steps

10 b^{2} + 21 b + 6 = 2 b

Move

2 b

to the left side

10 b^{2} + 19 b + 6 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 10 \cdot 6}{2 \cdot 10}

1 9^{2} - 4 \cdot 10 \cdot 6 = 11

b_{1, 2} = \frac{- 19 \pm 11}{2 \cdot 10}

Separate the solutions

b_{1} = \frac{- 19 + 11}{2 \cdot 10}, b_{2} = \frac{- 19 - 11}{2 \cdot 10}

b = \frac{- 19 + 11}{2 \cdot 10} : - \frac{2}{5}

b = \frac{- 19 - 11}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

b = - \frac{2}{5}, b = - \frac{3}{2}

x^{2} - 5 x + 2 = - 3 x + 10

(3 x - 7) (5 x - 12) = 0

16 x^{2} = 81

- (n + 2) = 15 (n + 7) n

4 x^{2} + 7 = 7 + 24 x

What are the solutions to the equation 10b^2+21b+6=2b ?
The solutions to the equation 10b^2+21b+6=2b are b=-2/5 ,b=-3/2
Find the zeros of 10b^2+21b+6=2b
The zeros of 10b^2+21b+6=2b are b=-2/5 ,b=-3/2