What are the solutions to the equation (3x-7)(5x-12)=0 ?

The solutions to the equation (3x-7)(5x-12)=0 are x= 7/3 ,x= 12/5

Find the zeros of (3x-7)(5x-12)=0

The zeros of (3x-7)(5x-12)=0 are x= 7/3 ,x= 12/5

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(3 x - 7) (5 x - 12) = 0

x = \frac{7}{3}, x = \frac{12}{5}

Decimal Notation

x = 2.33333 \dots, x = 2.4

Solution steps

(3 x - 7) (5 x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 7 = 0 or 5 x - 12 = 0

Solve

3 x - 7 = 0 : x = \frac{7}{3}

Solve

5 x - 12 = 0 : x = \frac{12}{5}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = \frac{12}{5}

16 x^{2} = 81

- (n + 2) = 15 (n + 7) n

4 x^{2} + 7 = 7 + 24 x

4 (x + 2)^{2} - 46 = - 18

x, x^{2} + y^{2} = z

What are the solutions to the equation (3x-7)(5x-12)=0 ?
The solutions to the equation (3x-7)(5x-12)=0 are x= 7/3 ,x= 12/5
Find the zeros of (3x-7)(5x-12)=0
The zeros of (3x-7)(5x-12)=0 are x= 7/3 ,x= 12/5