What are the solutions to the equation 4(x+2)^2-46=-18 ?

The solutions to the equation 4(x+2)^2-46=-18 are x=sqrt(7)-2,x=-sqrt(7)-2

Find the zeros of 4(x+2)^2-46=-18

The zeros of 4(x+2)^2-46=-18 are x=sqrt(7)-2,x=-sqrt(7)-2

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4 (x + 2)^{2} - 46 = - 18

x = 7 - 2, x = - 7 - 2

Decimal Notation

x = 0.64575 \dots, x = - 4.64575 \dots

Solution steps

4 (x + 2)^{2} - 46 = - 18

Move

46

to the right side

4 (x + 2)^{2} = 28

Divide both sides by

4

(x + 2)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 7 : x = 7 - 2

Solve

x + 2 = - 7 : x = - 7 - 2

The solutions to the quadratic equation are:

x = 7 - 2, x = - 7 - 2

x, x^{2} + y^{2} = z

x^{2} - 14 x = - 13

x^{2} + x - 6

4 (x^{2} - 6) - 3 = 9

4 x^{2} - 25 = 0

What are the solutions to the equation 4(x+2)^2-46=-18 ?
The solutions to the equation 4(x+2)^2-46=-18 are x=sqrt(7)-2,x=-sqrt(7)-2
Find the zeros of 4(x+2)^2-46=-18
The zeros of 4(x+2)^2-46=-18 are x=sqrt(7)-2,x=-sqrt(7)-2