What are the solutions to the equation 2x(4-7x)=-9 ?

The solutions to the equation 2x(4-7x)=-9 are x=-(-4+sqrt(142))/(14),x=(4+sqrt(142))/(14)

Find the zeros of 2x(4-7x)=-9

The zeros of 2x(4-7x)=-9 are x=-(-4+sqrt(142))/(14),x=(4+sqrt(142))/(14)

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2 x (4 - 7 x) = - 9

x = - \frac{- 4 + 142}{14}, x = \frac{4 + 142}{14}

Decimal Notation

x = - 0.56545 \dots, x = 1.13688 \dots

Solution steps

2 x (4 - 7 x) = - 9

Expand

2 x (4 - 7 x) : 8 x - 14 x^{2}

8 x - 14 x^{2} = - 9

Move

9

to the left side

8 x - 14 x^{2} + 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 14 x^{2} + 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 14 ) \cdot 9}{2 ( - 14 )}

8^{2} - 4 (- 14) \cdot 9 = 2142

x_{1, 2} = \frac{- 8 \pm 2 142}{2 ( - 14 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 142}{2 ( - 14 )}, x_{2} = \frac{- 8 - 2 142}{2 ( - 14 )}

x = \frac{- 8 + 2 142}{2 ( - 14 )} : - \frac{- 4 + 142}{14}

x = \frac{- 8 - 2 142}{2 ( - 14 )} : \frac{4 + 142}{14}

The solutions to the quadratic equation are:

x = - \frac{- 4 + 142}{14}, x = \frac{4 + 142}{14}

x^{2} + 8 x + 17

0 = 30 + 3 t - \frac{9.8 t ^{2}}{2}

r^{2} - r + 49 = 0

x^{2} - 101 = - 1

2 v^{2} + 7 v + 5 = 0

What are the solutions to the equation 2x(4-7x)=-9 ?
The solutions to the equation 2x(4-7x)=-9 are x=-(-4+sqrt(142))/(14),x=(4+sqrt(142))/(14)
Find the zeros of 2x(4-7x)=-9
The zeros of 2x(4-7x)=-9 are x=-(-4+sqrt(142))/(14),x=(4+sqrt(142))/(14)