What are the solutions to the equation 150x^2+x=0 ?

The solutions to the equation 150x^2+x=0 are x=0,x=-1/150

Find the zeros of 150x^2+x=0

The zeros of 150x^2+x=0 are x=0,x=-1/150

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150 x^{2} + x = 0

x = 0, x = - \frac{1}{150}

Decimal Notation

x = 0, x = - 0.00666 \dots

Solution steps

150 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 150 \cdot 0}{2 \cdot 150}

1^{2} - 4 \cdot 150 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 150}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 150}, x_{2} = \frac{- 1 - 1}{2 \cdot 150}

x = \frac{- 1 + 1}{2 \cdot 150} : 0

x = \frac{- 1 - 1}{2 \cdot 150} : - \frac{1}{150}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{150}

x^{2} + 2 x + 17 = 0

4 x^{2} + 20 x = - 17

x^{2} - b x + 16

y, y^{2} = - x^{2}

x^{2} - 60 = 4 x

What are the solutions to the equation 150x^2+x=0 ?
The solutions to the equation 150x^2+x=0 are x=0,x=-1/150
Find the zeros of 150x^2+x=0
The zeros of 150x^2+x=0 are x=0,x=-1/150