What are the solutions to the equation 2x^2=-20 ?

The solutions to the equation 2x^2=-20 are x=sqrt(10)i,x=-sqrt(10)i

Find the zeros of 2x^2=-20

The zeros of 2x^2=-20 are x=sqrt(10)i,x=-sqrt(10)i

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2 x^{2} = - 20

x = 10 i, x = - 10 i

Solution steps

2 x^{2} = - 20

Divide both sides by

2

x^{2} = - 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 10, x = - - 10

- 10 = 10 i

- - 10 = - 10 i

x = 10 i, x = - 10 i

x^{2} - 4 x

x^{2} + 6 x + 10

x^{2} + 6 x + 25

x^{2} + 4 x = 0

x (x - 3) + 2 x (x + 4) = 12

What are the solutions to the equation 2x^2=-20 ?
The solutions to the equation 2x^2=-20 are x=sqrt(10)i,x=-sqrt(10)i
Find the zeros of 2x^2=-20
The zeros of 2x^2=-20 are x=sqrt(10)i,x=-sqrt(10)i