What are the solutions to the equation -6t^2+13t-5=0 ?

The solutions to the equation -6t^2+13t-5=0 are t= 1/2 ,t= 5/3

Find the zeros of -6t^2+13t-5=0

The zeros of -6t^2+13t-5=0 are t= 1/2 ,t= 5/3

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- 6 t^{2} + 13 t - 5 = 0

t = \frac{1}{2}, t = \frac{5}{3}

Decimal Notation

t = 0.5, t = 1.66666 \dots

Solution steps

- 6 t^{2} + 13 t - 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 6 ) ( - 5 )}{2 ( - 6 )}

1 3^{2} - 4 (- 6) (- 5) = 7

t_{1, 2} = \frac{- 13 \pm 7}{2 ( - 6 )}

Separate the solutions

t_{1} = \frac{- 13 + 7}{2 ( - 6 )}, t_{2} = \frac{- 13 - 7}{2 ( - 6 )}

t = \frac{- 13 + 7}{2 ( - 6 )} : \frac{1}{2}

t = \frac{- 13 - 7}{2 ( - 6 )} : \frac{5}{3}

The solutions to the quadratic equation are:

t = \frac{1}{2}, t = \frac{5}{3}

\frac{1}{5} x^{2} + 6 = 2 x

- 4 x^{2} + 20 x = 25

2 x^{2} + 15 x + 27 = 0

t, 15 = 11.11 + 6 t^{2}

x^{2} - 4 x - 5

What are the solutions to the equation -6t^2+13t-5=0 ?
The solutions to the equation -6t^2+13t-5=0 are t= 1/2 ,t= 5/3
Find the zeros of -6t^2+13t-5=0
The zeros of -6t^2+13t-5=0 are t= 1/2 ,t= 5/3