What are the solutions to the equation 2x^2+15x+27=0 ?

The solutions to the equation 2x^2+15x+27=0 are x=-3,x=-9/2

Find the zeros of 2x^2+15x+27=0

The zeros of 2x^2+15x+27=0 are x=-3,x=-9/2

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2 x^{2} + 15 x + 27 = 0

x = - 3, x = - \frac{9}{2}

Decimal Notation

x = - 3, x = - 4.5

Solution steps

2 x^{2} + 15 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 2 \cdot 27}{2 \cdot 2}

1 5^{2} - 4 \cdot 2 \cdot 27 = 3

x_{1, 2} = \frac{- 15 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 15 + 3}{2 \cdot 2}, x_{2} = \frac{- 15 - 3}{2 \cdot 2}

x = \frac{- 15 + 3}{2 \cdot 2} : - 3

x = \frac{- 15 - 3}{2 \cdot 2} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = - 3, x = - \frac{9}{2}

t, 15 = 11.11 + 6 t^{2}

x^{2} - 4 x - 5

30.252 x^{2} - 1290 x + 2946.667 = 0

y, 2 x^{2} + x y + y^{2} = 4

12 b^{2} + 21 b + 10 = 3 b^{2}

What are the solutions to the equation 2x^2+15x+27=0 ?
The solutions to the equation 2x^2+15x+27=0 are x=-3,x=-9/2
Find the zeros of 2x^2+15x+27=0
The zeros of 2x^2+15x+27=0 are x=-3,x=-9/2