What are the solutions to the equation 12b^2+21b+10=3b^2 ?

The solutions to the equation 12b^2+21b+10=3b^2 are b=-2/3 ,b=-5/3

Find the zeros of 12b^2+21b+10=3b^2

The zeros of 12b^2+21b+10=3b^2 are b=-2/3 ,b=-5/3

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12 b^{2} + 21 b + 10 = 3 b^{2}

b = - \frac{2}{3}, b = - \frac{5}{3}

Decimal Notation

b = - 0.66666 \dots, b = - 1.66666 \dots

Solution steps

12 b^{2} + 21 b + 10 = 3 b^{2}

Move

3 b^{2}

to the left side

9 b^{2} + 21 b + 10 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

2 1^{2} - 4 \cdot 9 \cdot 10 = 9

b_{1, 2} = \frac{- 21 \pm 9}{2 \cdot 9}

Separate the solutions

b_{1} = \frac{- 21 + 9}{2 \cdot 9}, b_{2} = \frac{- 21 - 9}{2 \cdot 9}

b = \frac{- 21 + 9}{2 \cdot 9} : - \frac{2}{3}

b = \frac{- 21 - 9}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

b = - \frac{2}{3}, b = - \frac{5}{3}

15 c^{2} - c - 20 = 3 c^{2}

2 x^{2} + 82 = - 24 x

- x^{2} - 9 x + 3 = 0

- 4 n^{2} - 1 = - 4 n

2 x (6 - 5 x) = - 7

What are the solutions to the equation 12b^2+21b+10=3b^2 ?
The solutions to the equation 12b^2+21b+10=3b^2 are b=-2/3 ,b=-5/3
Find the zeros of 12b^2+21b+10=3b^2
The zeros of 12b^2+21b+10=3b^2 are b=-2/3 ,b=-5/3