What are the solutions to the equation -x^2-9x+3=0 ?

The solutions to the equation -x^2-9x+3=0 are x=-(9+sqrt(93))/2 ,x=(sqrt(93)-9)/2

Find the zeros of -x^2-9x+3=0

The zeros of -x^2-9x+3=0 are x=-(9+sqrt(93))/2 ,x=(sqrt(93)-9)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} - 9 x + 3 = 0

x = - \frac{9 + 93}{2}, x = \frac{93 - 9}{2}

Decimal Notation

x = - 9.32182 \dots, x = 0.32182 \dots

Solution steps

- x^{2} - 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 9)^{2} - 4 (- 1) \cdot 3 = 93

x_{1, 2} = \frac{- ( - 9 ) \pm 93}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 93}{2 ( - 1 )}, x_{2} = \frac{- ( - 9 ) - 93}{2 ( - 1 )}

x = \frac{- ( - 9 ) + 93}{2 ( - 1 )} : - \frac{9 + 93}{2}

x = \frac{- ( - 9 ) - 93}{2 ( - 1 )} : \frac{93 - 9}{2}

The solutions to the quadratic equation are:

x = - \frac{9 + 93}{2}, x = \frac{93 - 9}{2}

- 4 n^{2} - 1 = - 4 n

2 x (6 - 5 x) = - 7

- 3 r^{2} - r - 10 = - 4 r^{2}

x^{2} + 10 x + 25 = 0

2 x^{2} + 4 = - 7 x

What are the solutions to the equation -x^2-9x+3=0 ?
The solutions to the equation -x^2-9x+3=0 are x=-(9+sqrt(93))/2 ,x=(sqrt(93)-9)/2
Find the zeros of -x^2-9x+3=0
The zeros of -x^2-9x+3=0 are x=-(9+sqrt(93))/2 ,x=(sqrt(93)-9)/2