What are the solutions to the equation roots r^2+1 ?

The solutions to the equation roots r^2+1 are r=i,r=-i

Find the zeros of roots r^2+1

The zeros of roots r^2+1 are r=i,r=-i

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roots

r^{2} + 1

r = i, r = - i

Solution steps

r^{2} + 1

The roots are the intercepts with the x-axis

(y = 0)

r^{2} + 1 = 0

Move

1

to the right side

r^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 1, r = - - 1

- 1 = i

- - 1 = - i

r = i, r = - i

2 x^{2} - 4 x = 2.5

y, 2 x^{2} + x y - y^{2} = 2

4 (5 x + 9)^{2} + 34 = 38

2 x^{2} + 7 x + 3 = 12

x^{2} - 6 x = - 6 x + 4

What are the solutions to the equation roots r^2+1 ?
The solutions to the equation roots r^2+1 are r=i,r=-i
Find the zeros of roots r^2+1
The zeros of roots r^2+1 are r=i,r=-i