What are the solutions to the equation solvefor x,x^2+2y^2=k^2 ?

The solutions to the equation solvefor x,x^2+2y^2=k^2 are x=sqrt(k^2-2y^2),x=-sqrt(k^2-2y^2)

Find the zeros of solvefor x,x^2+2y^2=k^2

The zeros of solvefor x,x^2+2y^2=k^2 are x=sqrt(k^2-2y^2),x=-sqrt(k^2-2y^2)

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solve for

x, x^{2} + 2 y^{2} = k^{2}

x = k^{2} - 2 y^{2}, x = - k^{2} - 2 y^{2}

Solution steps

x^{2} + 2 y^{2} = k^{2}

Move

2 y^{2}

to the right side

x^{2} = k^{2} - 2 y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = k^{2} - 2 y^{2}, x = - k^{2} - 2 y^{2}

- 5 x^{2} + 3 = 0

- 2 x^{2} + 7 = - 1

3 x^{2} - 36 x = - 93

m^{2} + 8 m + 5 = 0

(x + 9)^{2} = - 24

What are the solutions to the equation solvefor x,x^2+2y^2=k^2 ?
The solutions to the equation solvefor x,x^2+2y^2=k^2 are x=sqrt(k^2-2y^2),x=-sqrt(k^2-2y^2)
Find the zeros of solvefor x,x^2+2y^2=k^2
The zeros of solvefor x,x^2+2y^2=k^2 are x=sqrt(k^2-2y^2),x=-sqrt(k^2-2y^2)