What are the solutions to the equation 3x^2-36x=-93 ?

The solutions to the equation 3x^2-36x=-93 are x=6+sqrt(5),x=6-sqrt(5)

Find the zeros of 3x^2-36x=-93

The zeros of 3x^2-36x=-93 are x=6+sqrt(5),x=6-sqrt(5)

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3 x^{2} - 36 x = - 93

x = 6 + 5, x = 6 - 5

Decimal Notation

x = 8.23606 \dots, x = 3.76393 \dots

Solution steps

3 x^{2} - 36 x = - 93

Move

93

to the left side

3 x^{2} - 36 x + 93 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 \cdot 93}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 \cdot 93 = 65

x_{1, 2} = \frac{- ( - 36 ) \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 6 5}{2 \cdot 3}, x_{2} = \frac{- ( - 36 ) - 6 5}{2 \cdot 3}

x = \frac{- ( - 36 ) + 6 5}{2 \cdot 3} : 6 + 5

x = \frac{- ( - 36 ) - 6 5}{2 \cdot 3} : 6 - 5

The solutions to the quadratic equation are:

x = 6 + 5, x = 6 - 5

m^{2} + 8 m + 5 = 0

(x + 9)^{2} = - 24

0.5 x^{2} - 7 x = - 5 x

5 c^{2} - 21 c + 11 = - 4 c

- x^{2} + 160 x - 900 = 0

What are the solutions to the equation 3x^2-36x=-93 ?
The solutions to the equation 3x^2-36x=-93 are x=6+sqrt(5),x=6-sqrt(5)
Find the zeros of 3x^2-36x=-93
The zeros of 3x^2-36x=-93 are x=6+sqrt(5),x=6-sqrt(5)