What are the solutions to the equation solvefor w,V=(2w-5)^2 ?

The solutions to the equation solvefor w,V=(2w-5)^2 are w=(sqrt(V)+5)/2 ,w=(-sqrt(V)+5)/2

Find the zeros of solvefor w,V=(2w-5)^2

The zeros of solvefor w,V=(2w-5)^2 are w=(sqrt(V)+5)/2 ,w=(-sqrt(V)+5)/2

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solve for

w, V = (2 w - 5)^{2}

w = \frac{V + 5}{2}, w = \frac{- V + 5}{2}

Solution steps

V = (2 w - 5)^{2}

Switch sides

(2 w - 5)^{2} = V

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 w - 5 = V : w = \frac{V + 5}{2}

Solve

2 w - 5 = - V : w = \frac{- V + 5}{2}

The solutions to the quadratic equation are:

w = \frac{V + 5}{2}, w = \frac{- V + 5}{2}

a^{2} + 6 a - 26 = 0

3 p^{2} - 4 = - 24

x^{2} - 8 x - 56 = 0

x^{2} - 5 x - 1 = - 1

7 x^{2} - 847 = 0

What are the solutions to the equation solvefor w,V=(2w-5)^2 ?
The solutions to the equation solvefor w,V=(2w-5)^2 are w=(sqrt(V)+5)/2 ,w=(-sqrt(V)+5)/2
Find the zeros of solvefor w,V=(2w-5)^2
The zeros of solvefor w,V=(2w-5)^2 are w=(sqrt(V)+5)/2 ,w=(-sqrt(V)+5)/2