What are the solutions to the equation (5x+2)(-x-4)=0 ?

The solutions to the equation (5x+2)(-x-4)=0 are x=-2/5 ,x=-4

Find the zeros of (5x+2)(-x-4)=0

The zeros of (5x+2)(-x-4)=0 are x=-2/5 ,x=-4

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(5 x + 2) (- x - 4) = 0

x = - \frac{2}{5}, x = - 4

Decimal Notation

x = - 0.4, x = - 4

Solution steps

(5 x + 2) (- x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 2 = 0 or - x - 4 = 0

Solve

5 x + 2 = 0 : x = - \frac{2}{5}

Solve

- x - 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - 4

3 x^{2} + 42 x = - 171

4 x^{2} + 36 x = - 77

x, 0 = 3 m^{2} x^{2} + 2 m x - 5

4 (x + 7)^{2} = 16

5 (x - 3)^{2} = - 225

What are the solutions to the equation (5x+2)(-x-4)=0 ?
The solutions to the equation (5x+2)(-x-4)=0 are x=-2/5 ,x=-4
Find the zeros of (5x+2)(-x-4)=0
The zeros of (5x+2)(-x-4)=0 are x=-2/5 ,x=-4