What are the solutions to the equation 9k^2+42k-15=0 ?

The solutions to the equation 9k^2+42k-15=0 are k= 1/3 ,k=-5

Find the zeros of 9k^2+42k-15=0

The zeros of 9k^2+42k-15=0 are k= 1/3 ,k=-5

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9 k^{2} + 42 k - 15 = 0

k = \frac{1}{3}, k = - 5

Decimal Notation

k = 0.33333 \dots, k = - 5

Solution steps

9 k^{2} + 42 k - 15 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 9 ( - 15 )}{2 \cdot 9}

4 2^{2} - 4 \cdot 9 (- 15) = 48

k_{1, 2} = \frac{- 42 \pm 48}{2 \cdot 9}

Separate the solutions

k_{1} = \frac{- 42 + 48}{2 \cdot 9}, k_{2} = \frac{- 42 - 48}{2 \cdot 9}

k = \frac{- 42 + 48}{2 \cdot 9} : \frac{1}{3}

k = \frac{- 42 - 48}{2 \cdot 9} : - 5

The solutions to the quadratic equation are:

k = \frac{1}{3}, k = - 5

4 y^{2} + 17 y + 12 = 0

3 x^{2} + 228 = 54 x

y, 2 x y^{2} - 3 x^{2} y = 6 x

8 x - 2 x^{2} = 1

x^{2} + 25 = 0

What are the solutions to the equation 9k^2+42k-15=0 ?
The solutions to the equation 9k^2+42k-15=0 are k= 1/3 ,k=-5
Find the zeros of 9k^2+42k-15=0
The zeros of 9k^2+42k-15=0 are k= 1/3 ,k=-5