What are the solutions to the equation 3(x+5)^2-13=-1 ?

The solutions to the equation 3(x+5)^2-13=-1 are x=-3,x=-7

Find the zeros of 3(x+5)^2-13=-1

The zeros of 3(x+5)^2-13=-1 are x=-3,x=-7

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3 (x + 5)^{2} - 13 = - 1

x = - 3, x = - 7

Solution steps

3 (x + 5)^{2} - 13 = - 1

Move

13

to the right side

3 (x + 5)^{2} = 12

Divide both sides by

3

(x + 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 4 : x = - 3

Solve

x + 5 = - 4 : x = - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

10 x^{2} = 6 x

4 x^{2} - 20 x + 25 = 0

- 7 x = x^{2} + 6

4 x^{2} + 4 x + 1 = 0

4 x^{2} + 73 = 36 x

What are the solutions to the equation 3(x+5)^2-13=-1 ?
The solutions to the equation 3(x+5)^2-13=-1 are x=-3,x=-7
Find the zeros of 3(x+5)^2-13=-1
The zeros of 3(x+5)^2-13=-1 are x=-3,x=-7