What are the solutions to the equation factor 4x^2+4x+1=0 ?

The solutions to the equation factor 4x^2+4x+1=0 are x=-1/2

Find the zeros of factor 4x^2+4x+1=0

The zeros of factor 4x^2+4x+1=0 are x=-1/2

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4 x^{2} + 4 x + 1 = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4 x^{2} + 4 x + 1 = 0

Factor

4 x^{2} + 4 x + 1 : (2 x + 1)^{2}

(2 x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

4 x^{2} + 73 = 36 x

(x + 4)^{2} = - 90

2 x^{2} + 2 x - 112 = 0

3 x^{2} - 6 x = - 25

4 x^{2} + 20 x = - 29

What are the solutions to the equation factor 4x^2+4x+1=0 ?
The solutions to the equation factor 4x^2+4x+1=0 are x=-1/2
Find the zeros of factor 4x^2+4x+1=0
The zeros of factor 4x^2+4x+1=0 are x=-1/2