What are the solutions to the equation 3x^2-6x=-25 ?

The solutions to the equation 3x^2-6x=-25 are x=1+isqrt(22/3),x=1-isqrt(22/3)

Find the zeros of 3x^2-6x=-25

The zeros of 3x^2-6x=-25 are x=1+isqrt(22/3),x=1-isqrt(22/3)

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3 x^{2} - 6 x = - 25

x = 1 + i \frac{22}{3}, x = 1 - i \frac{22}{3}

Solution steps

3 x^{2} - 6 x = - 25

Move

25

to the left side

3 x^{2} - 6 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 25}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 25 : 266 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 66 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 66 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 66 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 66 i}{2 \cdot 3} : 1 + i \frac{22}{3}

x = \frac{- ( - 6 ) - 2 66 i}{2 \cdot 3} : 1 - i \frac{22}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{22}{3}, x = 1 - i \frac{22}{3}

4 x^{2} + 20 x = - 29

7 x^{2} - 16 = 5 x^{2}

x^{2} - 96 = 4 x

- 3 x^{2} + 4 x - 9 = 2 x^{2} + 3

x^{2} - 9 x - 21 = 0

What are the solutions to the equation 3x^2-6x=-25 ?
The solutions to the equation 3x^2-6x=-25 are x=1+isqrt(22/3),x=1-isqrt(22/3)
Find the zeros of 3x^2-6x=-25
The zeros of 3x^2-6x=-25 are x=1+isqrt(22/3),x=1-isqrt(22/3)