What are the solutions to the equation 2y(4y+3)=9 ?

The solutions to the equation 2y(4y+3)=9 are y= 3/4 ,y=-3/2

Find the zeros of 2y(4y+3)=9

The zeros of 2y(4y+3)=9 are y= 3/4 ,y=-3/2

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2 y (4 y + 3) = 9

y = \frac{3}{4}, y = - \frac{3}{2}

Decimal Notation

y = 0.75, y = - 1.5

Solution steps

2 y (4 y + 3) = 9

Expand

2 y (4 y + 3) : 8 y^{2} + 6 y

8 y^{2} + 6 y = 9

Move

9

to the left side

8 y^{2} + 6 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 ( - 9 )}{2 \cdot 8}

6^{2} - 4 \cdot 8 (- 9) = 18

y_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- 6 + 18}{2 \cdot 8}, y_{2} = \frac{- 6 - 18}{2 \cdot 8}

y = \frac{- 6 + 18}{2 \cdot 8} : \frac{3}{4}

y = \frac{- 6 - 18}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

y = \frac{3}{4}, y = - \frac{3}{2}

x^{2} - 9 x + c

180 = 0.05 s^{2} + 1.1 s

y, y^{4} = y^{2} - x^{2}

2 x^{2} - 5 x - 6

x^{2} + 5 x - 36 = 0

What are the solutions to the equation 2y(4y+3)=9 ?
The solutions to the equation 2y(4y+3)=9 are y= 3/4 ,y=-3/2
Find the zeros of 2y(4y+3)=9
The zeros of 2y(4y+3)=9 are y= 3/4 ,y=-3/2