What are the solutions to the equation roots 2x^2-5x-6 ?

The solutions to the equation roots 2x^2-5x-6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4

Find the zeros of roots 2x^2-5x-6

The zeros of roots 2x^2-5x-6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4

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roots

2 x^{2} - 5 x - 6

x = \frac{5 + 73}{4}, x = \frac{5 - 73}{4}

Solution steps

2 x^{2} - 5 x - 6

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 6) = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 2}

x = \frac{- ( - 5 ) + 73}{2 \cdot 2} : \frac{5 + 73}{4}

x = \frac{- ( - 5 ) - 73}{2 \cdot 2} : \frac{5 - 73}{4}

The solutions to the quadratic equation are:

x = \frac{5 + 73}{4}, x = \frac{5 - 73}{4}

x^{2} + 5 x - 36 = 0

2 (x - 2)^{2} - 39 = - 31

x^{2} + 8 x - 24 = 3 x

x, x^{2} + y^{2} + z^{2} = 0

x^{2} + 2 x = - 2 x

What are the solutions to the equation roots 2x^2-5x-6 ?
The solutions to the equation roots 2x^2-5x-6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4
Find the zeros of roots 2x^2-5x-6
The zeros of roots 2x^2-5x-6 are x=(5+sqrt(73))/4 ,x=(5-sqrt(73))/4