What are the solutions to the equation x^2+8x-24=3x ?

The solutions to the equation x^2+8x-24=3x are x=3,x=-8

Find the zeros of x^2+8x-24=3x

The zeros of x^2+8x-24=3x are x=3,x=-8

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x^{2} + 8 x - 24 = 3 x

x = 3, x = - 8

Solution steps

x^{2} + 8 x - 24 = 3 x

Move

3 x

to the left side

x^{2} + 5 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 24) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 1}, x_{2} = \frac{- 5 - 11}{2 \cdot 1}

x = \frac{- 5 + 11}{2 \cdot 1} : 3

x = \frac{- 5 - 11}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 3, x = - 8

x, x^{2} + y^{2} + z^{2} = 0

x^{2} + 2 x = - 2 x

3 x^{2} - 14 x + 4 = 0

x, (x - h)^{2} + (y - k)^{2} = r^{2}

2 (x + 2)^{2} - 41 = - 9

What are the solutions to the equation x^2+8x-24=3x ?
The solutions to the equation x^2+8x-24=3x are x=3,x=-8
Find the zeros of x^2+8x-24=3x
The zeros of x^2+8x-24=3x are x=3,x=-8