What are the solutions to the equation 9x^2+60x+95=-5 ?

The solutions to the equation 9x^2+60x+95=-5 are x=-10/3

Find the zeros of 9x^2+60x+95=-5

The zeros of 9x^2+60x+95=-5 are x=-10/3

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9 x^{2} + 60 x + 95 = - 5

x = - \frac{10}{3}

Decimal Notation

x = - 3.33333 \dots

Solution steps

9 x^{2} + 60 x + 95 = - 5

Move

5

to the left side

9 x^{2} + 60 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 9 \cdot 100}{2 \cdot 9}

6 0^{2} - 4 \cdot 9 \cdot 100 = 0

x_{1, 2} = \frac{- 60 \pm 0}{2 \cdot 9}

x = \frac{- 60}{2 \cdot 9}

\frac{- 60}{2 \cdot 9} = - \frac{10}{3}

x = - \frac{10}{3}

The solution to the quadratic equation is:

x = - \frac{10}{3}

4 z^{2} - 11 z + 4 = 0

x^{2} + 4 x + 5 = 0

x^{2} - 22 x + 121 = 81

x^{2} + 8 x + 16 = 15

3 x^{2} - 4 x + 2

What are the solutions to the equation 9x^2+60x+95=-5 ?
The solutions to the equation 9x^2+60x+95=-5 are x=-10/3
Find the zeros of 9x^2+60x+95=-5
The zeros of 9x^2+60x+95=-5 are x=-10/3