What are the solutions to the equation roots x^2+4x+1 ?

The solutions to the equation roots x^2+4x+1 are x=-2+sqrt(3),x=-2-sqrt(3)

Find the zeros of roots x^2+4x+1

The zeros of roots x^2+4x+1 are x=-2+sqrt(3),x=-2-sqrt(3)

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roots

x^{2} + 4 x + 1

x = - 2 + 3, x = - 2 - 3

Solution steps

x^{2} + 4 x + 1

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 1 = 23

x_{1, 2} = \frac{- 4 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 3}{2 \cdot 1}

x = \frac{- 4 + 2 3}{2 \cdot 1} : - 2 + 3

x = \frac{- 4 - 2 3}{2 \cdot 1} : - 2 - 3

The solutions to the quadratic equation are:

x = - 2 + 3, x = - 2 - 3

x^{2} + 2 x - 2

6 w^{2} - 7 w - 3 = 0

2 w^{2} - 12 w + 18 = 0

x^{2} + 8 x + 15 = 0

y, x^{2} + y^{2} + 1 = 0

What are the solutions to the equation roots x^2+4x+1 ?
The solutions to the equation roots x^2+4x+1 are x=-2+sqrt(3),x=-2-sqrt(3)
Find the zeros of roots x^2+4x+1
The zeros of roots x^2+4x+1 are x=-2+sqrt(3),x=-2-sqrt(3)