What are the solutions to the equation 2x^2-8=120 ?

The solutions to the equation 2x^2-8=120 are x=8,x=-8

Find the zeros of 2x^2-8=120

The zeros of 2x^2-8=120 are x=8,x=-8

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2 x^{2} - 8 = 120

x = 8, x = - 8

Solution steps

2 x^{2} - 8 = 120

Move

8

to the right side

2 x^{2} = 128

Divide both sides by

2

x^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 64, x = - 64

64 = 8

- 64 = - 8

x = 8, x = - 8

x^{2} - a

12 x^{2} - 216 x + 504 = 0

x, b^{2} x^{2} + a^{2} y^{2} = a^{2} b^{2}

x^{2} - 2 x - 13

15 q^{2} + 31 q + 15 = 5

What are the solutions to the equation 2x^2-8=120 ?
The solutions to the equation 2x^2-8=120 are x=8,x=-8
Find the zeros of 2x^2-8=120
The zeros of 2x^2-8=120 are x=8,x=-8