What are the solutions to the equation 12x^2-216x+504=0 ?

The solutions to the equation 12x^2-216x+504=0 are x=9+sqrt(39),x=9-sqrt(39)

Find the zeros of 12x^2-216x+504=0

The zeros of 12x^2-216x+504=0 are x=9+sqrt(39),x=9-sqrt(39)

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12 x^{2} - 216 x + 504 = 0

x = 9 + 39, x = 9 - 39

Decimal Notation

x = 15.24499 \dots, x = 2.75500 \dots

Solution steps

12 x^{2} - 216 x + 504 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 216 ) \pm ( - 216 ) ^{2} - 4 \cdot 12 \cdot 504}{2 \cdot 12}

(- 216)^{2} - 4 \cdot 12 \cdot 504 = 2439

x_{1, 2} = \frac{- ( - 216 ) \pm 24 39}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 216 ) + 24 39}{2 \cdot 12}, x_{2} = \frac{- ( - 216 ) - 24 39}{2 \cdot 12}

x = \frac{- ( - 216 ) + 24 39}{2 \cdot 12} : 9 + 39

x = \frac{- ( - 216 ) - 24 39}{2 \cdot 12} : 9 - 39

The solutions to the quadratic equation are:

x = 9 + 39, x = 9 - 39

x, b^{2} x^{2} + a^{2} y^{2} = a^{2} b^{2}

x^{2} - 2 x - 13

15 q^{2} + 31 q + 15 = 5

12 x^{2} - 32 = 0

- 5 x^{2} + x = 0

What are the solutions to the equation 12x^2-216x+504=0 ?
The solutions to the equation 12x^2-216x+504=0 are x=9+sqrt(39),x=9-sqrt(39)
Find the zeros of 12x^2-216x+504=0
The zeros of 12x^2-216x+504=0 are x=9+sqrt(39),x=9-sqrt(39)