What are the solutions to the equation roots-(x-2)^2+4 ?

The solutions to the equation roots-(x-2)^2+4 are x=4,x=0

Find the zeros of roots-(x-2)^2+4

The zeros of roots-(x-2)^2+4 are x=4,x=0

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roots

- (x - 2)^{2} + 4

x = 4, x = 0

Solution steps

- (x - 2)^{2} + 4

The roots are the intercepts with the x-axis

(y = 0)

- (x - 2)^{2} + 4 = 0

Move

4

to the right side

- (x - 2)^{2} = - 4

Divide both sides by

- 1

(x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

4 x^{2} + 37 = - 20 x

x^{2} - 61 x + 900 = 0

- 2 x^{2} - 3 = 8 x + 6

- 3 x^{2} - 4 x + 2

4 x^{2} + 9 x - 7 = 2

What are the solutions to the equation roots-(x-2)^2+4 ?
The solutions to the equation roots-(x-2)^2+4 are x=4,x=0
Find the zeros of roots-(x-2)^2+4
The zeros of roots-(x-2)^2+4 are x=4,x=0