What is the answer to solvefor y,x^2-xy+2y-2=0 ?

The answer to solvefor y,x^2-xy+2y-2=0 is y=(-x^2+2)/(-x+2);\quad x\ne 2

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solvefor y,x^2-xy+2y-2=0

solve for

y, x^{2} - x y + 2 y - 2 = 0

y = \frac{- x ^{2} + 2}{- x + 2}; x \neq = 2

Solution steps

x^{2} - x y + 2 y - 2 = 0

Move

x^{2}

to the right side

- x y + 2 y - 2 = - x^{2}

Move

2

to the right side

- x y + 2 y = - x^{2} + 2

Factor

- x y + 2 y : y (- x + 2)

y (- x + 2) = - x^{2} + 2

Divide both sides by

- x + 2; x \neq = 2

y = \frac{- x ^{2} + 2}{- x + 2}; x \neq = 2

6 x^{2} - 8 x + 6 = 0

y, y^{2} - x^{2} = 0

6 x = 2 x^{2} - 7 x + 14

x, x y^{4} + x^{2} y = x + 3 y

x^{2} + 29.4 x - 756.3 = 0

What is the answer to solvefor y,x^2-xy+2y-2=0 ?
The answer to solvefor y,x^2-xy+2y-2=0 is y=(-x^2+2)/(-x+2);\quad x\ne 2