What are the solutions to the equation 8p^2+14p-9=6 ?

The solutions to the equation 8p^2+14p-9=6 are p= 3/4 ,p=-5/2

Find the zeros of 8p^2+14p-9=6

The zeros of 8p^2+14p-9=6 are p= 3/4 ,p=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 p^{2} + 14 p - 9 = 6

p = \frac{3}{4}, p = - \frac{5}{2}

Decimal Notation

p = 0.75, p = - 2.5

Solution steps

8 p^{2} + 14 p - 9 = 6

Move

6

to the left side

8 p^{2} + 14 p - 15 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

1 4^{2} - 4 \cdot 8 (- 15) = 26

p_{1, 2} = \frac{- 14 \pm 26}{2 \cdot 8}

Separate the solutions

p_{1} = \frac{- 14 + 26}{2 \cdot 8}, p_{2} = \frac{- 14 - 26}{2 \cdot 8}

p = \frac{- 14 + 26}{2 \cdot 8} : \frac{3}{4}

p = \frac{- 14 - 26}{2 \cdot 8} : - \frac{5}{2}

The solutions to the quadratic equation are:

p = \frac{3}{4}, p = - \frac{5}{2}

4 y^{2} + 25 = - 20 y

2 (x + 4)^{2} + 44 = 46

- 4 x^{2} + 3 x + 8 = 0

x^{2} + 9 x + 20 = 0

- x^{2} = - 2 x + 4

What are the solutions to the equation 8p^2+14p-9=6 ?
The solutions to the equation 8p^2+14p-9=6 are p= 3/4 ,p=-5/2
Find the zeros of 8p^2+14p-9=6
The zeros of 8p^2+14p-9=6 are p= 3/4 ,p=-5/2