What are the solutions to the equation -4x^2+3x+8=0 ?

The solutions to the equation -4x^2+3x+8=0 are x=-(-3+sqrt(137))/8 ,x=(3+sqrt(137))/8

Find the zeros of -4x^2+3x+8=0

The zeros of -4x^2+3x+8=0 are x=-(-3+sqrt(137))/8 ,x=(3+sqrt(137))/8

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- 4 x^{2} + 3 x + 8 = 0

x = - \frac{- 3 + 137}{8}, x = \frac{3 + 137}{8}

Decimal Notation

x = - 1.08808 \dots, x = 1.83808 \dots

Solution steps

- 4 x^{2} + 3 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 8}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 8 = 137

x_{1, 2} = \frac{- 3 \pm 137}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 137}{2 ( - 4 )}, x_{2} = \frac{- 3 - 137}{2 ( - 4 )}

x = \frac{- 3 + 137}{2 ( - 4 )} : - \frac{- 3 + 137}{8}

x = \frac{- 3 - 137}{2 ( - 4 )} : \frac{3 + 137}{8}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 137}{8}, x = \frac{3 + 137}{8}

x^{2} + 9 x + 20 = 0

- x^{2} = - 2 x + 4

x^{2} - 2 x + c

x^{2} - 18 x + 145 = 0

4 z^{2} - 4 z - 15 = 0

What are the solutions to the equation -4x^2+3x+8=0 ?
The solutions to the equation -4x^2+3x+8=0 are x=-(-3+sqrt(137))/8 ,x=(3+sqrt(137))/8
Find the zeros of -4x^2+3x+8=0
The zeros of -4x^2+3x+8=0 are x=-(-3+sqrt(137))/8 ,x=(3+sqrt(137))/8