What are the solutions to the equation 5(2x+9)^2-21=4 ?

The solutions to the equation 5(2x+9)^2-21=4 are x=(sqrt(5)-9)/2 ,x=(-sqrt(5)-9)/2

Find the zeros of 5(2x+9)^2-21=4

The zeros of 5(2x+9)^2-21=4 are x=(sqrt(5)-9)/2 ,x=(-sqrt(5)-9)/2

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5 (2 x + 9)^{2} - 21 = 4

x = \frac{5 - 9}{2}, x = \frac{- 5 - 9}{2}

Decimal Notation

x = - 3.38196 \dots, x = - 5.61803 \dots

Solution steps

5 (2 x + 9)^{2} - 21 = 4

Move

21

to the right side

5 (2 x + 9)^{2} = 25

Divide both sides by

5

(2 x + 9)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 9 = 5 : x = \frac{5 - 9}{2}

Solve

2 x + 9 = - 5 : x = \frac{- 5 - 9}{2}

The solutions to the quadratic equation are:

x = \frac{5 - 9}{2}, x = \frac{- 5 - 9}{2}

9 b^{2} + 12 b + 5 = 1

p^{2} + 3 = - 10

2 x^{2} + 20 x + 28

x^{2} - 14 = - 5

y, x^{2} - x y + y^{2} = 1

What are the solutions to the equation 5(2x+9)^2-21=4 ?
The solutions to the equation 5(2x+9)^2-21=4 are x=(sqrt(5)-9)/2 ,x=(-sqrt(5)-9)/2
Find the zeros of 5(2x+9)^2-21=4
The zeros of 5(2x+9)^2-21=4 are x=(sqrt(5)-9)/2 ,x=(-sqrt(5)-9)/2