What are the solutions to the equation p^2+3=-10 ?

The solutions to the equation p^2+3=-10 are p=sqrt(13)i,p=-sqrt(13)i

Find the zeros of p^2+3=-10

The zeros of p^2+3=-10 are p=sqrt(13)i,p=-sqrt(13)i

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p^{2} + 3 = - 10

p = 13 i, p = - 13 i

Solution steps

p^{2} + 3 = - 10

Move

3

to the right side

p^{2} = - 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - 13, p = - - 13

- 13 = 13 i

- - 13 = - 13 i

p = 13 i, p = - 13 i

2 x^{2} + 20 x + 28

x^{2} - 14 = - 5

y, x^{2} - x y + y^{2} = 1

9 x^{2} - 30 x + 26 = 0

10 x^{2} - 4 x = 8

What are the solutions to the equation p^2+3=-10 ?
The solutions to the equation p^2+3=-10 are p=sqrt(13)i,p=-sqrt(13)i
Find the zeros of p^2+3=-10
The zeros of p^2+3=-10 are p=sqrt(13)i,p=-sqrt(13)i