What are the solutions to the equation 10x^2-4x=8 ?

The solutions to the equation 10x^2-4x=8 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5

Find the zeros of 10x^2-4x=8

The zeros of 10x^2-4x=8 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5

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10 x^{2} - 4 x = 8

x = \frac{1 + 21}{5}, x = \frac{1 - 21}{5}

Decimal Notation

x = 1.11651 \dots, x = - 0.71651 \dots

Solution steps

10 x^{2} - 4 x = 8

Move

8

to the left side

10 x^{2} - 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 10 ( - 8 )}{2 \cdot 10}

(- 4)^{2} - 4 \cdot 10 (- 8) = 421

x_{1, 2} = \frac{- ( - 4 ) \pm 4 21}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 21}{2 \cdot 10}, x_{2} = \frac{- ( - 4 ) - 4 21}{2 \cdot 10}

x = \frac{- ( - 4 ) + 4 21}{2 \cdot 10} : \frac{1 + 21}{5}

x = \frac{- ( - 4 ) - 4 21}{2 \cdot 10} : \frac{1 - 21}{5}

The solutions to the quadratic equation are:

x = \frac{1 + 21}{5}, x = \frac{1 - 21}{5}

\frac{1}{4} (x + 2)^{2} = 27

1 - 1.1 x^{2} = 0

x, x^{2} + y^{2} = c x

2 x^{2} + 4 x - 20 = 0

10 x^{2} + 6 x - 30 = 0

What are the solutions to the equation 10x^2-4x=8 ?
The solutions to the equation 10x^2-4x=8 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5
Find the zeros of 10x^2-4x=8
The zeros of 10x^2-4x=8 are x=(1+sqrt(21))/5 ,x=(1-sqrt(21))/5