What are the solutions to the equation 1/4 (x+2)^2=27 ?

The solutions to the equation 1/4 (x+2)^2=27 are x=6sqrt(3)-2,x=-6sqrt(3)-2

Find the zeros of 1/4 (x+2)^2=27

The zeros of 1/4 (x+2)^2=27 are x=6sqrt(3)-2,x=-6sqrt(3)-2

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\frac{1}{4} (x + 2)^{2} = 27

x = 63 - 2, x = - 63 - 2

Decimal Notation

x = 8.39230 \dots, x = - 12.39230 \dots

Solution steps

\frac{1}{4} (x + 2)^{2} = 27

Multiply both sides by

4

(x + 2)^{2} = 108

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 108 : x = 63 - 2

Solve

x + 2 = - 108 : x = - 63 - 2

The solutions to the quadratic equation are:

x = 63 - 2, x = - 63 - 2

1 - 1.1 x^{2} = 0

x, x^{2} + y^{2} = c x

2 x^{2} + 4 x - 20 = 0

10 x^{2} + 6 x - 30 = 0

4 x^{2} - 8 x = - 3

What are the solutions to the equation 1/4 (x+2)^2=27 ?
The solutions to the equation 1/4 (x+2)^2=27 are x=6sqrt(3)-2,x=-6sqrt(3)-2
Find the zeros of 1/4 (x+2)^2=27
The zeros of 1/4 (x+2)^2=27 are x=6sqrt(3)-2,x=-6sqrt(3)-2