What are the solutions to the equation 0=x^2+8x+7 ?

The solutions to the equation 0=x^2+8x+7 are x=-1,x=-7

Find the zeros of 0=x^2+8x+7

The zeros of 0=x^2+8x+7 are x=-1,x=-7

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0 = x^{2} + 8 x + 7

x = - 1, x = - 7

Solution steps

0 = x^{2} + 8 x + 7

Switch sides

x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 6}{2 \cdot 1}

x = \frac{- 8 + 6}{2 \cdot 1} : - 1

x = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

2 y^{2} - 19 y + 17 = - 3 y^{2}

x^{2} + 20 x - 3500 = 0

0 = 2 (x + 1)^{2} + 3

y, x^{2} + 2 x y - y^{2} + x = 2

x^{2} + 7 x = 0

What are the solutions to the equation 0=x^2+8x+7 ?
The solutions to the equation 0=x^2+8x+7 are x=-1,x=-7
Find the zeros of 0=x^2+8x+7
The zeros of 0=x^2+8x+7 are x=-1,x=-7