What are the solutions to the equation r^2+20r+1000=0 ?

The solutions to the equation r^2+20r+1000=0 are r=-10+30i,r=-10-30i

Find the zeros of r^2+20r+1000=0

The zeros of r^2+20r+1000=0 are r=-10+30i,r=-10-30i

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r^{2} + 20 r + 1000 = 0

r = - 10 + 30 i, r = - 10 - 30 i

Solution steps

r^{2} + 20 r + 1000 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 1000}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 1000 : 60 i

r_{1, 2} = \frac{- 20 \pm 60 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 20 + 60 i}{2 \cdot 1}, r_{2} = \frac{- 20 - 60 i}{2 \cdot 1}

r = \frac{- 20 + 60 i}{2 \cdot 1} : - 10 + 30 i

r = \frac{- 20 - 60 i}{2 \cdot 1} : - 10 - 30 i

The solutions to the quadratic equation are:

r = - 10 + 30 i, r = - 10 - 30 i

x^{2} - 2 x + 3

x^{2} + 4 x + 3 = 0

f, f (x + 2) = (x + 2)^{2} + 1

3 x^{2} - 2 x + 5 = 10 x + 1

x^{2} + 36

What are the solutions to the equation r^2+20r+1000=0 ?
The solutions to the equation r^2+20r+1000=0 are r=-10+30i,r=-10-30i
Find the zeros of r^2+20r+1000=0
The zeros of r^2+20r+1000=0 are r=-10+30i,r=-10-30i