What are the solutions to the equation factor x^2+4x+3=0 ?

The solutions to the equation factor x^2+4x+3=0 are x=-1,x=-3

Find the zeros of factor x^2+4x+3=0

The zeros of factor x^2+4x+3=0 are x=-1,x=-3

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x^{2} + 4 x + 3 = 0

x = - 1, x = - 3

Solution steps

x^{2} + 4 x + 3 = 0

Factor

x^{2} + 4 x + 3 : (x + 1) (x + 3)

(x + 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

f (x) = (x + 2) = (x + 2)^{2} + 1

3 x^{2} - 2 x + 5 = 10 x + 1

x^{2} + 36

x^{2} + 4 x

4 (x^{2} - 8) - 6 = - 2

What are the solutions to the equation factor x^2+4x+3=0 ?
The solutions to the equation factor x^2+4x+3=0 are x=-1,x=-3
Find the zeros of factor x^2+4x+3=0
The zeros of factor x^2+4x+3=0 are x=-1,x=-3