What are the solutions to the equation roots x^2+4x ?

The solutions to the equation roots x^2+4x are x=0,x=-4

Find the zeros of roots x^2+4x

The zeros of roots x^2+4x are x=0,x=-4

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roots

x^{2} + 4 x

x = 0, x = - 4

Solution steps

x^{2} + 4 x

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 1}, x_{2} = \frac{- 4 - 4}{2 \cdot 1}

x = \frac{- 4 + 4}{2 \cdot 1} : 0

x = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

4 (x^{2} - 8) - 6 = - 2

x^{2} - 5 x + 4

y^{2} + 8 y + 20 = 0

x^{2} + 7 x + c

x^{2} + x = 0

What are the solutions to the equation roots x^2+4x ?
The solutions to the equation roots x^2+4x are x=0,x=-4
Find the zeros of roots x^2+4x
The zeros of roots x^2+4x are x=0,x=-4