What are the solutions to the equation roots x^2-5x+4 ?

The solutions to the equation roots x^2-5x+4 are x=4,x=1

Find the zeros of roots x^2-5x+4

The zeros of roots x^2-5x+4 are x=4,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} - 5 x + 4

x = 4, x = 1

Solution steps

x^{2} - 5 x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

y^{2} + 8 y + 20 = 0

x^{2} + 7 x + c

x^{2} + x = 0

y, x^{2} + 3 x y + y^{2} = 5

x^{2} = 24 - 85

What are the solutions to the equation roots x^2-5x+4 ?
The solutions to the equation roots x^2-5x+4 are x=4,x=1
Find the zeros of roots x^2-5x+4
The zeros of roots x^2-5x+4 are x=4,x=1