What are the solutions to the equation roots x^2+7x+c ?

The solutions to the equation roots x^2+7x+c are x=(-7+sqrt(49-4c))/2 ,x=(-7-sqrt(49-4c))/2

Find the zeros of roots x^2+7x+c

The zeros of roots x^2+7x+c are x=(-7+sqrt(49-4c))/2 ,x=(-7-sqrt(49-4c))/2

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roots

x^{2} + 7 x + c

x = \frac{- 7 + 49 - 4 c}{2}, x = \frac{- 7 - 49 - 4 c}{2}

Solution steps

x^{2} + 7 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 7 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

7^{2} - 4 \cdot 1 \cdot c : 49 - 4 c

x_{1, 2} = \frac{- 7 \pm 49 - 4 c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 49 - 4 c}{2 \cdot 1}, x_{2} = \frac{- 7 - 49 - 4 c}{2 \cdot 1}

x = \frac{- 7 + 49 - 4 c}{2 \cdot 1} : \frac{- 7 + 49 - 4 c}{2}

x = \frac{- 7 - 49 - 4 c}{2 \cdot 1} : \frac{- 7 - 49 - 4 c}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 49 - 4 c}{2}, x = \frac{- 7 - 49 - 4 c}{2}

x^{2} + x = 0

y, x^{2} + 3 x y + y^{2} = 5

x^{2} = 24 - 85

x^{2} - 2 x^{1} = 0

2 (3 x + 2)^{2} = 26

What are the solutions to the equation roots x^2+7x+c ?
The solutions to the equation roots x^2+7x+c are x=(-7+sqrt(49-4c))/2 ,x=(-7-sqrt(49-4c))/2
Find the zeros of roots x^2+7x+c
The zeros of roots x^2+7x+c are x=(-7+sqrt(49-4c))/2 ,x=(-7-sqrt(49-4c))/2