What are the solutions to the equation roots x^2+2x+6 ?

The solutions to the equation roots x^2+2x+6 are x=-1+sqrt(5)i,x=-1-sqrt(5)i

Find the zeros of roots x^2+2x+6

The zeros of roots x^2+2x+6 are x=-1+sqrt(5)i,x=-1-sqrt(5)i

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roots

x^{2} + 2 x + 6

x = - 1 + 5 i, x = - 1 - 5 i

Solution steps

x^{2} + 2 x + 6

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 6 : 25 i

x_{1, 2} = \frac{- 2 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 5 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 5 i}{2 \cdot 1}

x = \frac{- 2 + 2 5 i}{2 \cdot 1} : - 1 + 5 i

x = \frac{- 2 - 2 5 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

x = - 1 + 5 i, x = - 1 - 5 i

x, x^{2} + x y + y^{3} = 0

x^{2} - 8 x + 16

x^{2} + 8 x + 12 = 0

16 m^{2} + 72 m + 83 = 0

(x - 2) (- 2 x - 3) = 0

What are the solutions to the equation roots x^2+2x+6 ?
The solutions to the equation roots x^2+2x+6 are x=-1+sqrt(5)i,x=-1-sqrt(5)i
Find the zeros of roots x^2+2x+6
The zeros of roots x^2+2x+6 are x=-1+sqrt(5)i,x=-1-sqrt(5)i