What are the solutions to the equation roots x^2-8x+16 ?

The solutions to the equation roots x^2-8x+16 are x=4

Find the zeros of roots x^2-8x+16

The zeros of roots x^2-8x+16 are x=4

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roots

x^{2} - 8 x + 16

x = 4

Solution steps

x^{2} - 8 x + 16

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

x^{2} + 8 x + 12 = 0

16 m^{2} + 72 m + 83 = 0

(x - 2) (- 2 x - 3) = 0

2 d^{2} = 8

x^{2} + 18 x + c

What are the solutions to the equation roots x^2-8x+16 ?
The solutions to the equation roots x^2-8x+16 are x=4
Find the zeros of roots x^2-8x+16
The zeros of roots x^2-8x+16 are x=4