What are the solutions to the equation roots x^2+18x+c ?

The solutions to the equation roots x^2+18x+c are x=-9+sqrt(-c+81),x=-sqrt(-c+81)-9

Find the zeros of roots x^2+18x+c

The zeros of roots x^2+18x+c are x=-9+sqrt(-c+81),x=-sqrt(-c+81)-9

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roots

x^{2} + 18 x + c

x = - 9 + - c + 81, x = - - c + 81 - 9

Solution steps

x^{2} + 18 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 18 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot c : 2 81 - c

x_{1, 2} = \frac{- 18 \pm 2 81 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 81 - c}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 81 - c}{2 \cdot 1}

x = \frac{- 18 + 2 81 - c}{2 \cdot 1} : - 9 + - c + 81

x = \frac{- 18 - 2 81 - c}{2 \cdot 1} : - - c + 81 - 9

The solutions to the quadratic equation are:

x = - 9 + - c + 81, x = - - c + 81 - 9

4 x^{2} + 20 x = - 5

3 x^{2} + 4 x + 9 = 8

d^{2} + 13 d + 19 = 0

8 t^{2} + 22 t + 15 = 0

x^{2} - 10 x = 0

What are the solutions to the equation roots x^2+18x+c ?
The solutions to the equation roots x^2+18x+c are x=-9+sqrt(-c+81),x=-sqrt(-c+81)-9
Find the zeros of roots x^2+18x+c
The zeros of roots x^2+18x+c are x=-9+sqrt(-c+81),x=-sqrt(-c+81)-9