What are the solutions to the equation d^2+13d+19=0 ?

The solutions to the equation d^2+13d+19=0 are d=(-13+sqrt(93))/2 ,d=(-13-sqrt(93))/2

Find the zeros of d^2+13d+19=0

The zeros of d^2+13d+19=0 are d=(-13+sqrt(93))/2 ,d=(-13-sqrt(93))/2

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d^{2} + 13 d + 19 = 0

d = \frac{- 13 + 93}{2}, d = \frac{- 13 - 93}{2}

Decimal Notation

d = - 1.67817 \dots, d = - 11.32182 \dots

Solution steps

d^{2} + 13 d + 19 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 19 = 93

d_{1, 2} = \frac{- 13 \pm 93}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- 13 + 93}{2 \cdot 1}, d_{2} = \frac{- 13 - 93}{2 \cdot 1}

d = \frac{- 13 + 93}{2 \cdot 1} : \frac{- 13 + 93}{2}

d = \frac{- 13 - 93}{2 \cdot 1} : \frac{- 13 - 93}{2}

The solutions to the quadratic equation are:

d = \frac{- 13 + 93}{2}, d = \frac{- 13 - 93}{2}

8 t^{2} + 22 t + 15 = 0

x^{2} - 10 x = 0

x^{2} + 10 x + 100

y^{2} - 8 y - 2 = 0

x, x^{2} - 3 y^{2} - 2 y + z^{2} - 4 z = - 5

What are the solutions to the equation d^2+13d+19=0 ?
The solutions to the equation d^2+13d+19=0 are d=(-13+sqrt(93))/2 ,d=(-13-sqrt(93))/2
Find the zeros of d^2+13d+19=0
The zeros of d^2+13d+19=0 are d=(-13+sqrt(93))/2 ,d=(-13-sqrt(93))/2