What are the solutions to the equation factor 8t^2+22t+15=0 ?

The solutions to the equation factor 8t^2+22t+15=0 are t=-5/4 ,t=-3/2

Find the zeros of factor 8t^2+22t+15=0

The zeros of factor 8t^2+22t+15=0 are t=-5/4 ,t=-3/2

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8 t^{2} + 22 t + 15 = 0

t = - \frac{5}{4}, t = - \frac{3}{2}

Decimal Notation

t = - 1.25, t = - 1.5

Solution steps

8 t^{2} + 22 t + 15 = 0

Factor

8 t^{2} + 22 t + 15 : (4 t + 5) (2 t + 3)

(4 t + 5) (2 t + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 t + 5 = 0 or 2 t + 3 = 0

Solve

4 t + 5 = 0 : t = - \frac{5}{4}

Solve

2 t + 3 = 0 : t = - \frac{3}{2}

The solutions to the quadratic equation are:

t = - \frac{5}{4}, t = - \frac{3}{2}

x^{2} - 10 x = 0

x^{2} + 10 x + 100

y^{2} - 8 y - 2 = 0

x, x^{2} - 3 y^{2} - 2 y + z^{2} - 4 z = - 5

2 c^{2} - 5 c - 14 = - 5

What are the solutions to the equation factor 8t^2+22t+15=0 ?
The solutions to the equation factor 8t^2+22t+15=0 are t=-5/4 ,t=-3/2
Find the zeros of factor 8t^2+22t+15=0
The zeros of factor 8t^2+22t+15=0 are t=-5/4 ,t=-3/2