What are the solutions to the equation 6b^2+6b-6=b ?

The solutions to the equation 6b^2+6b-6=b are b= 2/3 ,b=-3/2

Find the zeros of 6b^2+6b-6=b

The zeros of 6b^2+6b-6=b are b= 2/3 ,b=-3/2

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6 b^{2} + 6 b - 6 = b

b = \frac{2}{3}, b = - \frac{3}{2}

Decimal Notation

b = 0.66666 \dots, b = - 1.5

Solution steps

6 b^{2} + 6 b - 6 = b

Move

b

to the left side

6 b^{2} + 5 b - 6 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 6) = 13

b_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 6}

Separate the solutions

b_{1} = \frac{- 5 + 13}{2 \cdot 6}, b_{2} = \frac{- 5 - 13}{2 \cdot 6}

b = \frac{- 5 + 13}{2 \cdot 6} : \frac{2}{3}

b = \frac{- 5 - 13}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

b = \frac{2}{3}, b = - \frac{3}{2}

x^{2} - 4 x - 12 = 0

- 2 (x + 9) (x - 1)

2 a^{2} - a - 11 = - 3

2 x^{2} + 82 = - 24 x

y, x^{2} + x = y^{2} + y

What are the solutions to the equation 6b^2+6b-6=b ?
The solutions to the equation 6b^2+6b-6=b are b= 2/3 ,b=-3/2
Find the zeros of 6b^2+6b-6=b
The zeros of 6b^2+6b-6=b are b= 2/3 ,b=-3/2